LTC3406AB
Applications Information
For the feedback resistors, choose R1 = 316k. R2 can
then be calculated from Equation (2) to be:
R2
=
VOUT
0.6
−
1
R1=
1000k
(4)
2.2µH*
VIN
4
CIN†
VIN
3
SW
22pF
4.7µF
CER
LTC3406AB
2.5V, 600mA
VOUT
COUT**
10µF
1
5
CER
RUN VFB
GND
2
1M
316k *MURATA LQH32CN2R2M33
** TAIYO YUDEN JHK316BJ106ML
3406AB TA09a † TAIYO YUDEN JMK212BJ475MG
Figure 5 shows the complete circuit along with its ef-
ficiency curve.
100
VOUT = 2.5V
90
80
70
60
50
40
30
20
10
0
0.1
VIN = 2.7V
VIN = 3.6V
VIN = 4.2V
1
10
100
OUTPUT CURRENT (mA)
1000
3406B G03
Load Step
Load Step
VOUT
200mV/DIV
VOUT
100mV/DIV
IL
500mA/DIV
ILOAD
500mA/DIV
VIN = 3.6V
20µs/DIV
VOUT = 2.5V
ILOAD = 200mA TO 450mA
3406B F10
IL
500mA/DIV
ILOAD
500mA/DIV
Figure 5
VIN = 3.6V
20µs/DIV
VOUT = 2.5V
ILOAD = 300mA TO 600mA
3406B F16
14
For more information www.linear.com/LTC3406AB
3406abfb